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Can someone help me with chemistry – stoichiometry stuff?

April 26, 2017Chemistry help Mathematics stoichiometry stuff

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Can someone help me with chemistry – stoichiometry stuff?

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The mass loss is from the water in CuSO4 x 5H2O being driven off. Mass H2O = original mass – final mass = 1.245 – 0.832 = 0.413 g H2O 0.413 g H2O x (1 mole H2O / 18.0 g H2O) = 0.0229 moles H2O By the formula of the hydrate, CuSO4 x 5H2O, we know that there are 5 moles of H2O for every one mole of CuSO4 in the hydrate. 0.0229 moles H2O x (1 mole CuSO4 x 5H2O / 5 moles H2O) = 0.00459 moles CuSO4 x 5H2O 0.00459 moles CuSO4 x 5H2O x (249.7 g CuSO4 x 5H2O / 1 mole CuSO4 x 5H2O) = 1.15 g CuSO4 x 5H2O % CuSO4 x 5H2O = (mass CuSO4 x 5H2O / total sample mass) x 100% = (1.15 / 1.245) x 100% = 92.