How do i calculate the pH of an HCL solution when diluted?
37 % HCl is concentration HCl which has a density of *goes to look at bottle* 1.18 g/ml and is 11.97 Molar. You have 10g which is 10/1.18 = 8.5 ml I am assuming you diluted it by taking the overall weight to 100g which means you added 90 grams of water or 90 ml so you have a new volume of 98.5 ml Use the equation C1V1= C2V2 where C1 is the original concentration, V1 the volume of the original solution used, C2 the new concentration and V2 the new volume. So you have used 8.5 ml of a 11.96 molar solution an diluted it to 98.5 ml 8.5*11.96/98.5 = 1.032 molar. So the new concentration is 1 molar. PH is given by the negative log of the hydrogen ion concentration, As HCl is a strong acid you can assume it fully dissociated and you have 1 molar Hydrogen ions: PH= -log [H+] A concentration of 1 molar HCl is still going to give you a pH of 0. You can see from the equation that you need a hydrogen ion conc of about 0.1 to give a pH of 1 so you need to dilute by a factor of ten again i.e -log [0
