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How Do You Prepare 100 Ml 2N Hcl Solution In 500Ml Containing 590 Grams?

April 26, 2017Chemistry HCl Mathematics ML prepare solution

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How Do You Prepare 100 Ml 2N Hcl Solution In 500Ml Containing 590 Grams?

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This question is badly worded so I have to guess what you want. I guess that you want to make 100ml of 2N HCl starting from a solution that has a volume of 500ml and a mass of 590 grams. If so, then your original solution has a density of 590/500 = 1.18g/ml. This equates to a concentration of 36.23% mass/ volume, or 362.3g /litre Molar mass HCL = 1.008 + 35.453 = 36.461g Molarity of conc solution = 362.3/36.461 = 9.94 You want 2N solution. Because HCl is monoprotic acid, 2N = 2M. Use equation: C1V1 = C2V2 2*100 = 9.94*V2 V2 = 200/9.94 V2 = 20.13 ml conc acid Answer: dilute 20.13ml conc acid to 100ml solution and you have a 2N solution.