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How much carbon dioxide is produced from the combustion of 1000 cubic feet of natural gas?

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How much carbon dioxide is produced from the combustion of 1000 cubic feet of natural gas?

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A. If we start with 1000 cubic feet of natural gas (and assuming it is pure methane or CH4) at STP (standard temperature and pressure, i.e., temperature of 273&#176K = 0&#176C = 32&#176F and pressure of 1 atm = 14.7 psia = 760 torr), and burn it completely, here’s what we come up with: 1 cubic foot (cf) = 0.0283165 cubic meters (m3) and 1 m3 = 1000 liters (L) so 1 cf = 28.31685 L and 1000 cf = 28316.85 L Since 1 mole of a gas occupies 22.4 L at STP, 28316.85 L of CH4 contains 28316.85/22.4 = 1264.145 moles of CH4 (each mole of CH4 = approx. 16 g) If we burn CH4 completely, it follows this equation: CH4 + 2O2 => CO2 + 2H20 That is, for each mole of methane we get one mole of carbon dioxide. One mole of CO2 has a mass of approx. 44 g, so 1264.145 moles of CO2 has a mass of approx. 1264.145 x 44 or 55622.38 g A pound is about equivalent to 454 g, so 55622.38 g is about equivalent to 55622.38/454 or 122 lb That is, the complete combustion of 1000 cubic feet at STP of natural gas results in

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1000 CUBIC FEET= 122 LBS OF CO2. If we start with 1000 cubic feet of natural gas (and assuming it is pure methane or CH4) at STP (standard temperature and pressure, i.e., temperature of 273K = 0C = 32F and pressure of 1 atm = 14.7 psia = 760 torr), and burn it completely, here’s what we come up with: 1 cubic foot (cf) = 0.0283165 cubic meters (m3) and 1 m3 = 1000 liters (L) so 1 cf = 28.31685 L and 1000 cf = 28316.85 L Since 1 mole of a gas occupies 22.4 L at STP, 28316.85 L of CH4 contains 28316.85/22.4 = 1264.145 moles of CH4 (each mole of CH4 = approx. 16 g) If we burn CH4 completely, it follows this equation: CH4 + 2O2 => CO2 + 2H20 That is, for each mole of methane we get one mole of carbon dioxide. One mole of CO2 has a mass of approx. 44 g, so 1264.145 moles of CO2 has a mass of approx. 1264.145 x 44 or 55622.38 g A pound is about equivalent to 454 g, so 55622.38 g is about equivalent to 55622.38/454 or 122 lb That is, the complete combustion of 1000 cubic feet at STP of natural

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