How Much Water Flows Through The Sacramento River During a Flood Event?
Relationship of Flood Flows in the Sacramento River Flood Control System and the Magnitude of Water Produced Written by Tom Ellis The rate of flow in a river in cubic feet per second (cfs) can readily be converted to volume in acre-feet produced within 24 hours by doubling the rate of flow. That means 1,000 cfs is equal to 2,000 acre-feet per day which is enough water to cover 2,000 acres (approximately 3 square miles) one foot deep. To get a feel for the amount of water that is produced during a major flood event on the Sacramento River every 24 hours, you can double the design capacity of 600,000 cfs. That equals 1,200,000 acre-feet in one day, or enough water to cover 1,200,000 acres one foot deep. As an example of how quickly water can accumulate, consider the larger storage facilities on the River system if they were empty. Shasta Lake has a capacity of 4.5 million acre-feet. Therefore, a flood flow of 600,000 cfs would fill Shasta Lake in 3.75 days. Oroville Reservoir’s capacity
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