How much will a junk yard pay for a whole car?

Add your answer...

5 Answers

Not all junkyards accept cars (most do), but for the most part depending on the condition/size/type of car, you could get as low as $100 or as much as $500. Junkers are weighed and bought based on the scrap value, but some places will take into account valuable car parts for certain hard to find models or other qualifiers. You should shop around and even try ebay though.
Thanks for your feedback!

Related Videos

That depends, are you talking about a scrap yard or a auto salvage? A scrap yard, where they crush it and then grind it up will only take it after you remove all of the fluids and then they pay by the pound. I got $150 for a full sized 3/4 ton Dodge pick up truck last fall. If you are talking about a salvage yard where they remove the good parts and sell them then you are probably looking at $300 BUT it must be a car they want. They dont want a 1986 Chevy Celebrity. But they do want a 2001 Toyota Camry. more

It really depends on how much your car wieghs and how much metal or parts are salvagaeble. You can calculate the cars wieght and check that days scrap prices. planetjunkcars.com generates a scrap price on the spot as well. Good luck.


It depends on the car type and how much scrap metal can be extracted out of it. Some auto salvage yards like cox auto parts, automotix and worldcarparts offer good deals and on the spot towing and pay in cash promptly and even provide a receipt which is beneficial for tax benefits too. If the vehicle has good parts left to retain, expect a better price overall.


Junkyards do not name their prices according to the make or model of cars, but instead they go by their weights. Hence, you can expect to get a really meager price tag unless you sell each individual spare part separately on their own if still in a good condition. Try enquiring at a few junkyards and enquire regarding their buying policies as they might have a different pricing method.

Not the answer you're looking for? Try asking your own question.