Important Notice: Our web hosting provider recently started charging us for additional visits, which was unexpected. In response, we're seeking donations. Depending on the situation, we may explore different monetization options for our Community and Expert Contributors. It's crucial to provide more returns for their expertise and offer more Expert Validated Answers or AI Validated Answers. Learn more about our hosting issue here.

How to balance the equation of C4H9OH + O2 >CO2 + H2O ?

0
Posted

How to balance the equation of C4H9OH + O2 >CO2 + H2O ?

0

The point of balancing an equation is to get the same number of each atom on each side. What I usually do (especially when there is water and oxygen) is balance the non oxygen and hydrogen atoms first. So you have 4 Carbon on the left side, and only one on the right. So you multiply the molecule containing Carbon on the right (CO2) by 4 to balance the carbons. Now you equation looks like this: C4H9OH + O2 –> 4 CO2 + H2O Now count the number of Hydrogens. You have 10 on the left side and 2 on the right side. Because the molecule containing the Hydrogen on the right has 2 hydrogen atoms, you only have to multiply by 5. Now your equation looks like this: C4H9OH + O2 –> 4 CO2 + 5 H2O Now count the Oxygens. You have 3 on the left side, and 13 on the right side. You need 10 more on the left side. So add 5 more molecules of O2, giving you 6 in all. Your balanced equation: C4H9OH + 6 O2 –> 4 CO2 + 5 H2O Now you can go back through and make sure you have the same number of each on each side.

Thanksgiving questions

*Sadly, we had to bring back ads too. Hopefully more targeted.