How would you extract copper from a mixture of metal sulphate + copper?
I think that you are asking about something that you are not understanding: If you take a solution of copper sulphate and you introduce a bar of metal that is higher than copper in the reactivity series, then a chemical reaction will occur, depositing copper metal as a precipitate and forming the metal sulphate in solution. This is normally demonstrated in the classroom using an iron nail and copper sulphate solution. The blue copper sulphate gradually turns a greener colour and the bright orange copper metal falls to the bottom of the beaker. Recover the copper metal by filtering it off from the soluble iron sulphate. I am not sure what you mean by “ensure that its mass is the same when operated with for several experiments” If you use a fixed concentration of CuSO4 solution, always of the same volume, a constant mass of Cu will be deposited with every experiment. Ther must always be some unreacted metal remaining.
