What is the concentration of the solution in g dm-3?
25cm3 of a solution of O.2M potassium hydroxide reacts with 30cm3 of a solution of nitric acid. What is the concentration of the acid in g dm-3? I just figured out what this question is about. It is describing the results of a titration experiment The 30 ml of One cubic decimeter = 10cm * 10cm * 10cm = 1000cubic cm = 1000 ml I just figured out what this question is about. It is describing the results of a titration experiment The 30 ml of nitric acid has neutralized the 25 ml of O.2M potassium hydroxide solution. KOH + HNO3 → KNO3 + HOH We need to determine the number of moles of HNO3 that reacted with the 25 ml of KOH. Then determine how many moles of KOH would be in a liter of solution, because molarity equals moles of solute per liter of solutiom A 0.2 m solution of KOH contains 0.2 moles of KOH per liter of solution 25 ml of the solution = 0.025 liters .025 liters * 0.2 moles/liter = 0.005moles of KOH reacting Since 1 mole of KOH reacts with 1 mole of nitric acid, 0.005 moles of KO