What is the percentage of barium in the compound?
Scooby, First we have to calculate the moles of BaSO4, from which we can get the moles of barium. From that, we get the grams of barium, and divide that by the initial weight of the compound: Moles BaSO4 = (0.0891 g/233.3909 g/mol ) = 3.82 x 10^-4 moles Moles Ba = Moles BaSO4 = 3.82 x 10^-4 moles Grams Ba = 3.82 x 10^-4 moles x 137.327 g/mole = 0.0524 g Percent barium in sample = 0.0524 g/0.269 g x 100% = 19.5% Hope that helped!