What is the solubility of Ca(OH)2 in .30 M NaOH?
This is the common ion effect which tends to decrease solubility of the compound in question Start out by writing an equation Ca(OH)2 <=======> Ca(2+) + 2OH- Think about le chatelier’s principle if you add OH- ions from NaOH then you shift the equilibrium to the left Ca(OH)2 Okay so start by writing the Ksp equation Equilibrium constant = product^coefficient/reactant^coefficient Ksp = [Ca2+][OH-]^2 We ignore solids in equilibrium constants because they usually are constant in equilibrium problems Ksp will almost never have a denominator So if X amount of Ca(OH)2 dissolves then X amount of Ca2+ is produced and 2X amount of OH is produced That’s according to our chemical equation where there is a 2 in front of Hydroxide and 1 in front of Ca2+ Okay so now let’s plug this in our equation however we must take into account the OH from NaOH NaOH is strong base 100% dissociate. .30 M NaOH will produce .30 OH- ions The total OH- ions can be calculated by adding OH from NaOH to the OH from Ca(OH
