What mass of hydrochloric acid would be needed to fully react with 25 grams of calcium carbonate?
The MW of CaCO3 =100 = 1 mole 100 g will react with 2 moles of hydrochloric acid 1 mole of HCL = 36.5 g thus 25 g will react with (25/100) * 36.5 g HCL= 9.125g HCL but this pure HCL gas Lab HCL is at 11 Normal concentrated in the bottle. One must not work )re HSE) with HCL gas and concentrated HCL in a school lab to do this directly as first step, so you dilute the HCL with water or you can buy 1 N HCL . 1 N HCL is in supply in school, already prepared and certified. 1 N HCL has 36.5 g HCL per litre Thus you need 9,125 g of HCL in your volume taken This volume will be (9.125 / 36.5) *1000 ml The volume required equivalent to 9.125g HCL is 250 mls.