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What’s the difference between calling a function as &foo and foo()?

April 26, 2017difference foo function

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What’s the difference between calling a function as &foo and foo()?

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When you call a function as &foo, you allow that function access to your current @_ values, and you by-pass prototypes. That means that the function doesn’t get an empty @_, it gets yours! While not strictly speaking a bug (it’s documented that way in the perlsub manpage), it would be hard to consider this a feature in most cases.