Can someone help me solve this null hypothesis problem?
The null hypothesis is H0: There is no relationship between gender and interest in ecological issues. HA: There is a relationship between gender and interest in ecological issues. Perform a Chi-square test. Since all of the cell frequencies are larger than 5, no continuity correction is required. Table of observed frequencies: ———–High———–Low——-To… Male——-40————60———-1… Female—60————40———-100 Total—–100———–100———-2… Table of expected frequencies: ———–High———–Low——-To… Male——-50————50———-1… Female—50————50———-100 Total—–100———–100———-2… To find the expected frequency for any cell: (row total)(column total) / Grand total = (100)(100)/200=50 Compute Chi-square: Σ (O(i)-E(i))^2 / E(i) = (40-50)^2/50 + (60-50)^2/50 + (60-50)^2/50+(40-50)^2/50 =2+2+2+2=8 What is the critical value? 6.635 What is the calculated value ? 8 Do you accept or reject the null? Crit
