How to find the height of a triangle….iscoceles and not?
Well you have to use trigonometry for non-isoceles triangles, but you can use pythagora’s theorem for isoceles ones. I don’t know if you’ve learnt it yet, but assuming you do, here’s how you do it. (Too difficult to teach the whole thing if you don’t.) Since sin of an angle is opposite over hypotenuse, for the first example we have: Let x be the height sin 40 = x/ 6.5 x = 6.5 sin 40 = approximately 4.1781 (Leave to 5 significant figures for calculation of the area!) Since the area of a triangle is 1/2 x base x height, the triangle’s area is 0.5 x 9 x 4.1781 = approx 18.8 units^2 For the second example, you have an isoceles triangle. I think you made a mistake and gave the height as 10, but I’ll do this example with the hypotenuse as 10. First, find half the length of the base: Half of base = 8/2 = 4 Notice that if you cut the triangle in half, you get two similar right-angle triangles. Taking either of these triangles: By pythagora’s theorem, 4^2 + h^2 = 10^2, where h is the height. h^
